Question

A ladder 25m long rests against a wall. If the top of the ladder reaches at a point 24m from the base of the wall find the distance of the foot of the ladder from the base of the wall.

Answer 1

Hello.

Easy Question :)

Height of the wall - 24m.

Height of the ladder - 25m.

Distance of the wall from the ladders' foot - 7m.

Using Pythagoras Theorem,

$(bc) {}^{2} = (ab) {}^{2} - (ab) {}^{2} \\ \\x {}^{2} = 25 {}^{2} - {24}^{2} \\ x { }^{2} = 625 - 576 \\ x {}^{2} = 49 \\ x = \sqrt{49} \\ x = 7$

steps-

1. Draw the given situation and you will realise that a right angled triangle is forming.
2. Note the given distances or heights.
3. Apply Pythagoras.

Please mark the branliest...

Answer 2

Answer:

7m

Step-by-step explanation:

ABC is a right triangle.

so, by pythagoras theorem,

$AC^2=BC^2+AB^2\\25^2=BC^2+24^2\\625=BC^2+576\\BC^2=625-576\\BC^2=49\\BC=\sqrt{49}\\BC=7$

SO required distance is 7m