Question

A ladder 25m long was rested along a wall such that the top touched the wall at hight of 24m from ground how far is foot of the ladder from the wall

Answer 1

hey...
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this will form a right angle triangle so pythogorus theorm will be applied
so,
let the distance between the foot of the ladder and wall be x,
${x }^{2} + {24}^{2} = {25 }^{2}$
${x }^{2} + 576 = 625$
${x}^{2} = 625 - 576$
${x}^{2} = 49$
$x = \sqrt{49}$
$x = 7$
hope this helped
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