Math, asked by sheetalnambiar2020, 9 months ago

A ladder 26 m long is resting against a vertical wall. The foot of the ladder is 10m away from the base of the wall. How high up the wall will the ladder reach? Show steps wise Pythagoras theorem

Answers

Answered by k047

--------------------------------------

Here is the solution:

--------------------------------------

*Assuming that the 10cm is meant to be 10m

Find the height of the wall:

a² + b² = c²

a² + 10² = 26²

a² = 26² - 10²

a² =576

a ≈ 24 m

Answer: The height of the wall from the ground to the top of the ladder is 24 m

$<html> <head> <meta name="viewport"the content="width=device-width, initial-scale=1"> <style> Body{ background-color: yellow; font-family: cursive; } .glow{ font-size: 80px; color: #fff; text-align: center; -webkit-animation: glow 1s ease-in-out infinite alternate; -moz-animation: glow 1s ease-in-out infinite alternate; animation: glow 1s ease-in-out infinite alternate; } @-webkit-keyframes glow{ from{ text-shadow: 0 0 10px #fff, 0 0 20px #fff, 0 0 30px #e60073, 0 0 40px #e60073, 0 0 50px #e60073, 0 0 60px #e60073, 0 0 70px #e60073; } } </style> </head> <body> <h1 class="glow">K047</h1> </body> </html>$

Answered by manyadixit12

Answer:

24 m

Step-by-step explanation:

Lenght of ladder = 26m

Lenght between base of wall to ladder = 10m

Let the height of ladder till wall be 'x'.

26² = 10² + x²

676 = 100 + x²

676 - 100 = x²

x² = 576

x = $\sqrt{576}$

x = 24 m

Previous Question

Next Question