A ladder 26 m long reaches a window of a building 24 m
above the ground. Find the distance of the foot of the ladder from the building.
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Answer:
In △PQR, we have
PR
2
=PQ
2
+QR
2
(By Pythagoras theorem)
(26)
2
=(24)
2
+QR
2
QR
2
=676−576=100
⇒QR=
100
⇒QR=10
The distance of the foot of the ladder fro the wall is 10 m.
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