a ladder 37 m long reaches a window which is 12 m above the ground, on the one side of the street . keeping it's foot at the same point, the ladder is turned to the other side of the street to reach a window at a height of 35 m. find the width of the street.
Answers
Answer: The ladder, the wall and the distance between the foot of the ladder and the foot of the wall makes a right angle triangle, with the right angle at foot of the wall. As per the above figure a = Wall = 12 M, c = ladder = 37 m and b = the distance between the foot of the ladder and the foot of the wall = ?.
So as per Pythagoras theorem:
Hypotenuse2= Base2+ Perpendicular2.
Base =√Hypotenuse2-Perpendicular2. =√372- 122=√1369 - 144 =√1225 = 35 m.
So the distance between the foot of the ladder and the foot of the wall = 35 m.
For the second case:
The ladder, the wall and the distance between the foot of the ladder and the foot of the wall makes a right angle triangle, with the right angle at the foot of the wall. As per the above figure, AB= Wall = 35 m, AC = ladder = 37 m and BC = the distance between the foot of the ladder and the foot of the wall = ?.
So as per Pythagoras theorem:
Hypotenuse2= Base2+ Perpendicular2.
Base =√Hypotenuse2-Perpendicular2. =√372- 352=√1369 - 1225 =√144 = 12 m.
So the distance between the foot of the ladder and the foot of the wall = 12 m.
So the width of the road = 35 + 12 = 47 m.
Ans: 47 mtrs.
Credit goes to @marufakhatun07043
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Answer:
the width of the street
=47m
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Step-by-step explanation:
Use the hypotenuse formula
c²=a²+b²
First condition
37²=12²+b²
=>1369=144+b²
=>1369-144=b²
=>1225=b²
=>35=b
2nd condition
37²=35²+b²
=>1369=1225+b²
=>1369-1225=b²
=>144=b²
=>12=b
Therefore the width of the street
=1st condition's b + 2nd condition's b
= 35+12
=47m