Question

A ladder 4.5 M long is placed against a wall in such a way that the foot of the ladder is 2.7 m away from the wall find the height of the wall to which the ladder reach

Answer 1

by P.T
root under(4.5)^2-(2.7)^2=3.6

Answer 2

by Pythagoras theorem
h²=p²+ b²
(4.5)²=p²+(2.7)²
20.25=p²+7.29
p²=20.75-7.29=12.96
p=
$\sqrt{12.96}$
=3.6m