Question

a ladder 4.5 m long is placed against a wall in such a way that the foot of the ladder is 2.7 metre away from the wall find the height of the wall to which the ladder reaches
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Answer 1

Answer:

Manishpaul

Ambitious

31 answers

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by P.T

root under(4.5)^2-(2.7)^2=

Answer 2

Given,

Length of the ladder = 4.5 m

The foot of the ladder = 2.7 m

To find,

Height of the wall to which the ladder reaches

Solution,

The ladder, vertical wall and foot of the ladder constitutes a right angle triangle.

We know that as per pythogogean theorem

Hypoteneuse² = base² + perpendicular²

So, 4.5² = 2.7² + perpendicular²

or, perpendicular² = 4.5² - 2.7²

or, perpendicular² = (4.5 + 2.7) (4.5 - 2.7)

or, perpendicular² = (7.2) (1.8)

or, perpendicular² = 9*0.8 * 9 * 0.2

or, perpendicular² = 9* 9 * 0.16

or perpendicular = $\sqrt 81*0.16$

or, perpendicular = 9 * 0.4

or, perpendicular = 3.6

Hence, the height of the wall to which the ladder reaches is 3.6 m