a ladder 45 m long is placed against a wall in such a way that the foot of the ladder is 27m away from the wall find the height of the wall to which the ladder reaches?
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Answered by
1
Step-by-step explanation:
hight of wall =√45^2-27^2
=36m
Answered by
0
Answer:
it can be picturized like a right angled triangle
base= 27m
hypotenuse =45
so height^2 = 45^2 -27^2
h^2=1296
h= 36 m
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