a ladder 6.5mlong,rests against a vertical wall.if the foot of the ladder is 2.5mfrom the foot of the wall.find upto howmuch does the ladder reach
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Length of ladder=6.5m
distance of ladder from foot of wall=2.5m
hight of ladder,=?
By solve this question by hight and distance ....?.
Suppose AB is a hight of wall and,AC is alength of ladder and AB is perpendicular on side BC.....
So,
ABC is a right angle triangle right angle at B....
By phatagoreous theorem.....
AC2=AB2+BC2
=(6.5)2=AB2+(2.5)2
=42.25=AB2+6.25
:AB2=36
so,
AB=6m......
Height of wall =6m
Golu...sharma....
distance of ladder from foot of wall=2.5m
hight of ladder,=?
By solve this question by hight and distance ....?.
Suppose AB is a hight of wall and,AC is alength of ladder and AB is perpendicular on side BC.....
So,
ABC is a right angle triangle right angle at B....
By phatagoreous theorem.....
AC2=AB2+BC2
=(6.5)2=AB2+(2.5)2
=42.25=AB2+6.25
:AB2=36
so,
AB=6m......
Height of wall =6m
Golu...sharma....
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