Question

a ladder 61 long reaches the fall of a house 60 m above the ground how far it is the food from the house

Answer 1

let AB and AC be the height of house and length of ladder respectively.

then by Pythagoras theorem, we have

AC²=AB²+BC²,

61²=60²+BC²,

61²-60²=BC²,

(61+60)(61-60)=BC²,

hence

121×1=BC²,

BC²=121,

BC=√121,

then

BC=11 me