Question

A ladder 61 m long reaches a window which is 60 m
above the ground on one side of a street. Keeping its foot
at the same point, the ladder is turned to the other side of
the street to reach a window 11 m high. Then the width
of the street is

Answer 1

Answer:

pls mark as brainliest if it's right ☺️

Answer 2

Width of the street is 71 m.

Given:

A ladder 61 m long reaches a window which is 60 m above the ground on one side of a street. Keeping its foot at the same point, the ladder is turned to the other side of the street to reach a window 11 m high.

To Find:

The width of the street.

Solution:

Given,

AB = 11 m

AC = 61 m

EC = 61 m

ED = 60 m

Let the width of the street be x.

In triangle ABC, applying Pythagoras theorem

AC² = AB² + BC²

61² = 11² + BC²

BC = √3600

BC = 60 m

In triangle ECD, applying Pythagoras theorem

EC² = ED² + CD²

61² = 60² + CD²

CD = √121

CD = 11 m

width of the street be x = CD + BC = 60 + 11 = 71 m.

Therefore, width of the street is 71 m.

#SPJ2