a ladder 6m long leaned against a wall. Its foot is 80cm away from base of the wall. What is the height the ladder reaches up? What's is the angle between the floor and the ladder?
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Answered by
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Answer:
if we take the ladder as AB such that B touches gound and the third point as C,then,
AB^2=BC^2+AC^2
FIND: BC
600^2=BC^2 + 80^2
360000=BC^2 + 6400
BC^2=360000-6400=3,53,600
BC=594.642.....cm(APPROX)ANS
Answered by
0
Step-by-step explanation:
First of all according to question
draw a right Triangle of three sides
let angles A,B and C
Now,
Ab^=Ac^-Bc^
Ab^=600^-80^
Ab^=360000-6400
Ab^=353600
Ab=594.642cm
approx
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