Question

. A ladder 'AB' of weight 300N and length 5m
is lying on a horizontal surface. Its centre of
gravity is at a distance of 2m' from end A. A
weight of 80N is attached at end B. The work
done in raising the ladder to the vertical
position with end 'A' in contact with the
ground is,
1) 500J 2) 1000J 3) 1150J 4) 1900J​

Answer 1

Answer:

workdone to raising 300N to 2 m

W = FS

= 300×2= 600J

workdone to raising 80N to 5m height

w= fs

= 80×5 = 400N

Total workdone = 600J+400J= 1000J

Answer 2

Answer:

workdone to raising 300N to 2 m

W = FS

= 300×2= 600J

workdone to raising 80N to 5m height

w= fs

= 80×5 = 400N

Total workdone = 600J+400J= 1000J

Explanation: