A ladder has rungs 25 cm apart .the rungs decrease uniformly in length from 45 cm to 25 cm at the top .if the top and bottom rungs are 2.5 metre apart , what is the length of the wood required for the rungs
Answers
Answered by
13
DISTANCE BETWEEN FIRST AND LAST RUNGS=2.5M=250CM
DISTANCE BETWEEN FIRST AND SECOND RUNGS=25CM
NUMBER OF RUNGS=250/25+1=11 RUNGS
So length of wood = Sn = n/2 (a + l )
=11/2 (45+25 )
=11/2 (70)
=385 cm
Answered by
18
distance between the top and bottom of rungs= 2.5m
=250cm
distance between 2 continuous rungs=25
so total number of rungs=250/25 +1=11
so,
n= 11
d=25
a=45
l=25
sn=n/2(a+l)
sn=11/2(45+25)
=11/2(70)
=11*35
thus sn=385cm
length of wood required to make the rungs=385cm
hope it helps!!!
=250cm
distance between 2 continuous rungs=25
so total number of rungs=250/25 +1=11
so,
n= 11
d=25
a=45
l=25
sn=n/2(a+l)
sn=11/2(45+25)
=11/2(70)
=11*35
thus sn=385cm
length of wood required to make the rungs=385cm
hope it helps!!!
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