Math, asked by adesai20, 10 months ago

a ladder is 100 m long and distance between bottom of the ladder and wall is 60m.what is the maximum size of the cube that can be placed between the wall and the ladder.; a ladder is 100 m long and distance between bottom of the ladder and wall is 60m.what is the maximum size of the cube that can be placed between the wall and the ladder.

Answers

Answered by amitnrw
1

Answer:

Edge of cube = 34.2857 m

Volume of cube = 40303 .2 m³

Step-by-step explanation:

Ladder is 100 m long

Distance between bottom of Ladder & wall = 60 m

Height of wall where ladder is reaching = H

H² = 100²  - 60²

=> H² = 10000 - 3600

=> H² = 6400

=> H = 80 m

Now to find maximum size of cube

let Say Cube has side = x m

if it is placed

there then we can see current triangle is divided into two right angle triangle & square

Area of current Triangle = (1/2) * Base * Height = (1/2) * 60 * 80 = 2400 m²

Area of bottom triangle  = (1/2) * (60-x) * x

Area of Square = x²

Area of upper Triangle = (1/2) * x * (80-x)

Sum of all these = 2400 m²

(1/2) * (60-x) * x + x²  + (1/2) * x * (80-x) = 2400

multiplying with 2 both sides

=> 60x - x²  + 2x² + 80x - x² = 4800

=> 140 x = 4800

=> x = 480/14

=> x = 240/7

=> x = 34.2857 m

Volume of cube = (240/7)³ = 40303 .2 m³

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