A ladder is 10meters long reaches a point 10m below the top of the vertical wall. from the foot of the ladder,the angle of elevation of the top of the vertical wall is 60°.find the height of the wall.
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Height of the wall is 16.66 m
Length of ladder = BD = 10m (Given)
Angle of elevation = 60° (Given)
As the ladder reaches the point of wall that is 10m below from the top of the wall, then AB = 10 m
In ΔBCD
Sin Ф = Perpendicular / Hypotenuse
Sin60 = BC/BD
√3/2 = BC/10
BC = 5√3
Height of wall = AB +BC
= 10 +5√3
= 16.6 m
Therefore, height of the wall is 16.66 m
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