a ladder is 41 m long reaches a building 9 m above the ground. Find the distance of the foot of the ladder from the building
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Answer:
Let AC be the ladder, AB be the wall.
Then in △ABC,
AC
2
=AB
2
+BC
2
(Pythagoras theorem)
17
2
=15
2
+BC
2
BC
2
=8
2
BC=8 m
Hence, the foot of the ladder is 8 m from the wall.
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