a ladder is an inclined at 60° to the floor it touches the wall at the point 0,8 find the equation
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The length of the ladder is 5 m.
The length of the ladder is 5 m.To find:
The length of the ladder is 5 m.To find:The length of the ladder whose foot is 2.5 m away from the wall.
The length of the ladder is 5 m.To find:The length of the ladder whose foot is 2.5 m away from the wall.Given:
The length of the ladder is 5 m.To find:The length of the ladder whose foot is 2.5 m away from the wall.Given:Distance between the wall and the foot of the ladder = 2.5 m
The length of the ladder is 5 m.To find:The length of the ladder whose foot is 2.5 m away from the wall.Given:Distance between the wall and the foot of the ladder = 2.5 mThe angle of elevation is “60°"
The length of the ladder is 5 m.To find:The length of the ladder whose foot is 2.5 m away from the wall.Given:Distance between the wall and the foot of the ladder = 2.5 mThe angle of elevation is “60°"Let the length of the ladder is L. The angle of elevation is 60°
The length of the ladder is 5 m.To find:The length of the ladder whose foot is 2.5 m away from the wall.Given:Distance between the wall and the foot of the ladder = 2.5 mThe angle of elevation is “60°"Let the length of the ladder is L. The angle of elevation is 60°By using cosine formulae
The length of the ladder is 5 m.To find:The length of the ladder whose foot is 2.5 m away from the wall.Given:Distance between the wall and the foot of the ladder = 2.5 mThe angle of elevation is “60°"Let the length of the ladder is L. The angle of elevation is 60°By using cosine formulae$$\begin{lgathered}\begin{array} { c } { \cos \theta = \frac { \text {Adjacent side} } { \text {Hypotenuse} } } \\\\ { \cos 60 ^ { \circ } = \frac { 2.5 } { L } } \end{array}\end{lgathered}$$
The length of the ladder is 5 m.To find:The length of the ladder whose foot is 2.5 m away from the wall.Given:Distance between the wall and the foot of the ladder = 2.5 mThe angle of elevation is “60°"Let the length of the ladder is L. The angle of elevation is 60°By using cosine formulae$$\begin{lgathered}\begin{array} { c } { \cos \theta = \frac { \text {Adjacent side} } { \text {Hypotenuse} } } \\\\ { \cos 60 ^ { \circ } = \frac { 2.5 } { L } } \end{array}\end{lgathered}$$The length of the ladder will be,
The length of the ladder is 5 m.To find:The length of the ladder whose foot is 2.5 m away from the wall.Given:Distance between the wall and the foot of the ladder = 2.5 mThe angle of elevation is “60°"Let the length of the ladder is L. The angle of elevation is 60°By using cosine formulae$$\begin{lgathered}\begin{array} { c } { \cos \theta = \frac { \text {Adjacent side} } { \text {Hypotenuse} } } \\\\ { \cos 60 ^ { \circ } = \frac { 2.5 } { L } } \end{array}\end{lgathered}$$The length of the ladder will be,$$\begin{lgathered}\begin{array} { c } { \text {Length } L = \frac { 2.5 } { \cos 60 ^ { \circ } } } \\\\ { L = \frac { 2.5 } { \frac { 1 } { 2 } } = 2.5 \times 2 } \\\\ { L = 5 \mathrm { m } } \end{array}\end{lgathered}$$
The length of the ladder is 5 m.To find:The length of the ladder whose foot is 2.5 m away from the wall.Given:Distance between the wall and the foot of the ladder = 2.5 mThe angle of elevation is “60°"Let the length of the ladder is L. The angle of elevation is 60°By using cosine formulae$$\begin{lgathered}\begin{array} { c } { \cos \theta = \frac { \text {Adjacent side} } { \text {Hypotenuse} } } \\\\ { \cos 60 ^ { \circ } = \frac { 2.5 } { L } } \end{array}\end{lgathered}$$The length of the ladder will be,$$\begin{lgathered}\begin{array} { c } { \text {Length } L = \frac { 2.5 } { \cos 60 ^ { \circ } } } \\\\ { L = \frac { 2.5 } { \frac { 1 } { 2 } } = 2.5 \times 2 } \\\\ { L = 5 \mathrm { m } } \end{array}\end{lgathered}$$Therefore, the length of the ladder is 5 m.