Question

A ladder is inclined at an angle of 30° with a wall. A man climbs this ladder at a speed of 3 cm/sec.
At what rate is he approaching the wall.
​

Answer 1

Step-by-step explanation:

According to the figure, let AC represent the magnitude of velocity vector from point C on ground to point A on the wall, that is AC= 2 m per s and ∠BAC=30

o

degree.

Then, by trigonometry, sin30

o

=

AC

BC

where BC is the magnitude of velocity vector from C to wall.

Then sin30

o

=

AC

BC

⇒

2

1

=

2m/s

BC

⇒BC=1m/s

Then he approaching the wall