Question

A ladder is leaning against a vertical wall. The ladder is 6m long and the foot of the ladder is 2m from the base of the wall. Find the angle the ladder makes with the wall.

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Angle\:made\:by\:ladder\:with\:wall}=sin{-1}(\frac{1}{3})}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

• In the given question information given about a ladder is leaning against a vertical wall. The ladder is 6m long and the foot of the ladder is 2m from the base of the wall.

• We have to find the angle made by the ladder with wall.

$\green{\underline \bold{Given :}} \\ : \implies \text{Length\:of\: ladder=6\:m}\\\\ :\implies \text{Distance\:between\:wall\:and\:foot\:of\:ladder=2\:m}\\ \\ \red{\underline \bold{To \: Find:}} \\ : \implies \text{Angle\:made\:by\:ladder\:with\:wall= ?}$

• Accroding to given question :

$\bold{In \: \triangle \: ABC} \\ : \implies sin\:\theta=\frac{\text{perpendicular}}{\text{hypotenuse}}\\ \\ : \implies sin\:\theta = \frac{distance\:between\:wall\:and\:foot\:of\:ladder}{length\:of\:ladder} \\ \\ : \implies sin\:\theta= \frac{2}{6} \\ \\ : \implies sin\:\theta=\frac{1}{3} \\ \\ \green{: \implies \theta = sin^{-1}(\frac{1}{3})}$