Question

A ladder is place in such a way that its foot is at distance of 7 metre from a wall and and it top reaches windowo24 metres about the ground determine the length of ladder

Answer 1

Answer:

Length of Ladder = 25 cm

Step-by-step explanation:

According to the question ABC is a triangle in which AB= 24 cm, BC = 7 cm

Applying pythagorus theorem

Since, ∠ABC = 90°

AB² + BC² = AC²

⇒24² + 7² = AC²

⇒576 + 49 = AC²

⇒625 = AC²

⇒25 cm = AC

Answer 2

AnswEr :

⋆ Refrence of Image is in the Diagram :

$\setlength{\unitlength}{1.5cm}\begin{picture}(6,2)\put(7.7,2.9){\large{A}}\put(7.7,1){\large{B}}\put(10.6,1){\large{C}}\put(8,1){\line(1,0){2.5}}\put(8,1){\line(0,2){1.9}}\put(10.5,1){\line(-4,3){2.5}}\put(7.3,2){\mathsf{\large{24 m}}}\put(9,0.7){\matsf{\large{7 m}}}\put(9.4,1.9){\mathsf{\large{? m}}}\put(8.2,1){\line(0,1){0.2}}\put(8,1.2){\line(3,0){0.2}}\end{picture}$

$\rule{150}{1}$

Let the AB be Distance of Window from Ground & AC be the Ladder on Window.

$\underline{\bigstar\:\textsf{By Pythagoras Theorem :}}$

$:\implies\tt AC^2 = AB^2 + BC^2\\\\\\:\implies\tt AC^2 =(24 \:m)^2 + (7 \:m)^2\\\\\\:\implies\tt AC^2 =(24 \:m \times 24 \:m) + (7 \:m \times 7 \:m)\\\\\\:\implies\tt AC^2 =576 \:m^2 + 49 \:m^2\\\\\\:\implies\tt AC^2 =625 \:m^2\\\\\\:\implies\tt AC =\sqrt{625 \:m^2}\\\\\\:\implies\tt AC=\sqrt{25 \:m \times 25 \:m}\\\\\\:\implies\boxed{\tt AC =25 \:m}$

⠀

$\therefore\:\underline{\textsf{Length of the Ladder will be \textbf{25 m.}}}$

$\rule{200}{2}$

• S H O R T C U T⠀T R I C K :

Simply Remember this Pythagorean Triplet, and Apply According to the Question.

$\begin{tabular}{|c |c | c|}\cline{1-3}p/b & b/p & h \\\cline{1-3}3 & 4 & 5 \\5 & 12 &13\\7 & 24&25 \\8 & 15&17\cline{1-2}\cline{1-3}\end{tabular}$

Here we find there are 7 and 24 are given, then we will simply take the missing term of that pair i.e. 25.

⠀

$\therefore\:\underline{\textsf{Length of the Ladder will be \textbf{25 m.}}}$