A ladder is placed against a wall of a building in such a way that the foot of the ladder is 4-5 m away from the building and height of building is 6 m. Find the length of ladder.
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The ladder forms a right angled triangle with the wall and the base with length of the ladder being the length of hypotenuse of this triangle.
Hypotenuse =25 m
Base =7 m
Height =25
2
−7
2
=24 m
Now the ladder slides. In the new position, the hypotenuse of the new right angled triangle will be the same.
The top slides down by a distance 4m. Hence, the height is 24−4=20 m. Let the base slide by a distance x. Therefore, hypotenuse =25 m
Base =(7+x) m
Height =20 m
By Pythagoras Theorem, we get
25
2
−20
2
=(7+x)
2
∴(7+x)=15
Hence, x=8
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i think 10.5m
it may be not correct please excuse
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