Question

A ladder is placed against a wall such that it reaches the top of the wall. The foot of the ladder is 1.5 metres away from the wall and the ladder is inclined at an angle of 600 with the ground. Find the height of the wall.​

Answer 1

Solution :-

Consider AB as the wall and AC as the ladder whose foot C is 1.5 m away from B

Take AB = x m and angle of inclination is 60°.

[ Refer to the attachment ]

We know that,

↪tan θ = AB/CB

• Substituting the values

↪tan 60° = x/1.5

• So we get

↪√3 = x/1.5

• By cross multiplication

↪x = √3 × 1.5 = 1.732 × 1.5

↪x = 2.5980 = 2.6m.

Hence,

• The height of wall is 2.6 m.

Answer 2

Consider AB as the wall and AC as the ladder whose foot C is 1.5 m away from B

Take AB = x m and angle of inclination is 60⁰

We know that

tan θ = AB/CB

Substituting the values

tan 60⁰ = x/1.5

So we get

√3 = x/1.5

By cross multiplication

x = √3 × 1.5 = 1.732 × 1.5

x = 2.5980 = 2.6

Hence, the height of wall is 2.6 m.