Question

A ladder is placed against a wall such that it touches it, 20 m above the ground. The foot of the
ladder is 15 m away from the wall. What is the length of the ladder?

Answer 1

Answer :

$\red{\bigstar}$ The length of the ladder is $\leadsto\underline{\boxed{\sf{25 m.}}}$

Step-by-step explanation :

Given that,

Distance from the wall = QR = 15m

Height of the ladder = PR = 20m

As, the wall will be the perpendicular to ground.

Then,

∴ ∠ PRQ = 90°

By using pythagoras theorem,

( PQ )² = ( PR )² + ( QR )²

By putting the values,

» PQ² = ( 20 )² + ( 15 )²

» PQ² = 400 + 225

» PQ² = 625

» PQ = √ 625

» PQ = 25

Hence, the length of the ladder is 25 m.

Now, Verification

» ( 25 )² = ( 20 )² + ( 15 )²

» 625 = 400 + 225

» 625 = 625

L.H.S = R.H.S

Hence, Verified