a ladder is placed against a wall such that its feet. is 2.5 m distance from the wall and its top reaches a window 6m above the ground. Find the length of ladder
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Let AB be the length of the ladder
BC be the distance from wall
AC be the height above the ground
By pythagoras theorem
AB^2=AC^2+BC^2
AB^2=6^2+2.5^2
AB^2=36+6.25
AB^2=42.25
AB=√42.25
AB=6.5m
Therefore the length of the ladder is 6.5m
BC be the distance from wall
AC be the height above the ground
By pythagoras theorem
AB^2=AC^2+BC^2
AB^2=6^2+2.5^2
AB^2=36+6.25
AB^2=42.25
AB=√42.25
AB=6.5m
Therefore the length of the ladder is 6.5m
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