Question

A ladder is placed against a wall such that its foot at a distance of 2.5m from the wall and its top reaches a window 6m above the ground . Find the length of the ladder. Explain with diagram.?

Answer 1

Answer:

6.25 m

Step-by-step explanation:

Let AC be the ladder and AB is the height of the window.

Given, BC = 2.5 m, AB = 6 m.

By Pythagoras theorem,

⇒ AC² = AB² + BC²

⇒ AC² = (6)² + (2.5)²

⇒ AC² = 36 + 6.25

⇒ AC² = 42.25

⇒ AC = 6.25 m.

Therefore, Length of the ladder = 6.25 m.

Hope it helps!

Answer 2

Step-by-step explanation:

The ladder, the ground and the wall forms a right angle triangle

a² + b² = c²

c² = 2.5² + 6²

c² = 42.25

c = √42.25

c = 6.5 m