Question

a ladder is placed against a wall such that its foot is at distance of 2.5m from the wall and its top reaches a window 6m above the ground. find the length of the ladder

Answer 1

Given :

• Distance from wall = 2.5m
• Height of window = 6m

To Find :

• Length of the ladder

Solution :

Let AB be the ladder and CA be the wall with the window at A.

Also BC = 2.5m and CA = 6m

From Pythagoras theorem,

AB² = BC² + CA²

= (2.5)² + (6)²

= ( 2.5 × 2.5 ) + ( 6 × 6 )

= 6.25 + 36

= 42.25

AB = $\sqrt{42.25}$

AB = 6.5

•°• Hence, The length of the ladder = 6.5m

Answer 2

Step-by-step explanation:

hope it will be helpful to you