Math, asked by Pronil42, 1 year ago

A ladder is placed against a wall such that its foot is at a distance of 5m from the wall.Its top reaches a window 5√3m above the ground.Find the length of the ladder.​

Answers

Answered by MsPRENCY
8

Correct Question :

• A ladder is placed against a wall such that it's foot is at a distance of 5m from the wall. It's top reaches a window  {5} \sqrt {3} m above the ground. Find the length of the ladder.

\bf {\huge{\underline {\boxed {\sf\purple {Answer : 10\:m}}}}}

\textsf {\underline {\underline{Step-By-Step\:Explanation}}}

\huge\sf\green {Given :}

• Distance of ladder from the wall is 5 m

• It's top reaches the window above the ground at 5 \sqrt {3} m.

\huge\sf\green {To\: Find :}

• The length of the ladder

\huge\sf\green {Solution :}

By pythagoreous theorem,

 {(AC)}^2 = (AB)^2 + ( BC)^2

 (AC)^2 = ( 5\sqrt {3})^2 + ( 5 )^2

  (AC)^2 = 75 + 25

 (AC)^2 = 100

 AC = \sqrt {100}

\therefore AC = 10 m

Answer : Length of the ladder is 10 m

\huge\mathscr\red {Be\:Brainly!!!}

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Answered by Rudra0936
10

Answer:

Given A ladder is placed against the wall such that the foot is 5 m away from the foot of the wall and The top of the ladder is 5√3 m above the ground / From the foot of the wall✓

Now we can see the from the above condition that the ladder and the wall along with make a right angle Where the angle between the wall and the ground is 90°

now \: from \: the \: triangle \: pqt \: which \: is \: in \: the \: attachment \: we \: hve \: height \: nd \: base \: measure \:

So A/Q we have to find the length of ladder that means we have to find the hypotenus of the ∆ PQT✓

______________________________________________

Let us find the hypotenus of the or the length of the ladder

Which is as follows:-

_____________________

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we will use pythagoras theorem ✓

hypotenus ^{2}  = base ^{2} + height ^{2}

qp =     \sqrt{qt ^{2} +pt ^{2}  }

 =  > qp =  \sqrt{5 ^{2} +( 5 \sqrt{3} ) ^{2}  }

 =  > qp  =  \sqrt{25 + 25 \times 3} .....(because \:  \sqrt{3 \: and \: square \: root \: get \:  cancelled} )

 =  >qp =  \sqrt{25 + 75}  \\  \\  =  > qp = \sqrt{100}  \\  \\  =  > qp = 10m \: ....(because  \sqrt{100}  = 10)

So the Length of the ladder is 10 m✓

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