Question

A ladder is placed against a wall such that its foot is at a distance of 2.5 m from the wall and its top reaches a window 6 m above the ground.Find the length of the ladder​

Answer 1

Step-by-step explanation:

Let the length of the ladder be x

By Pythagoras Theorem,

x^2 = 2.5^2 + 6^2

x^2 = 6.25 × 36

x^2 = 42.25

$\sqrt{42.25 } = 6.5m$