Question

a ladder is placed against a wall such that its foot is at a distance of 6 m from the wall and its top reaches a Window 8 metre above the ground find the length of the ladder​

Answer 1

Step-by-step explanation:

height of ladder²=foot distance²+top reaches window²

=✓36+64

✓100

=10

Answer 2

Answer:

PR is the ladder.

QR is the distance between base and ladder.

PQ is height of the window.

$\bigstar \: \underline{\sf Now,by \: using \: Phythagoras \: theorem \: we \: get : }$

$:\implies \sf (Hypotenuse)^{2} = (Perpendicular)^{2} + (Base)^{2}$

$:\implies \sf (PR)^2 = (PQ)^2 + (QR)^2$

$:\implies \sf PR^2 = (6 \: m)^{2} + (8 \: m)^{2}$

$:\implies \sf PR^2 = 36 + 64$

$:\implies \sf PR= \sqrt{36 + 64}$

$:\implies \sf PR= \sqrt{100 \: m}$

$:\implies \underline{ \boxed{ \sf PR= 10 \: meter}}$

$\therefore\:\underline{\textsf{Length of the ladder is \textbf{10 meter}}}.$