Question

A ladder is placed against a wall such that its foot is at a distance of 2.5 m from the wall and it's top reach a window 6m above the ground.find the length of ladder

Answer 1

according to Pythagoras therom

per^2+base^2=hyp^2

6^2 +2.5^2=hypo^2
36+6.25 =hyp^2
hyp^2 =42.25

hyp =√42.25
hyp=6.4. =the length of ladder