Question

A ladder is placed aganist a walll such that its foot is at a distance of 2.5m from the walll and its top reaches a window 6 meter above the ground find the lenght of yhe ladder

Answer 1

The Ladder is 6.5 m long

To solve this, we can use the Pythagorean Theorem, which is $a^2+b^2=c^2$

First, we need to solve the equation for c. This will give us $c =\sqrt{a^2+b^2}$

Lets have the distance, 2.5 m, be b. And 6 m be a

Now, lets substitute in the values into the equation and get $\sqrt{2.5^2+6^2} = c$

This simplifies to $\sqrt{42.25} = c$

Which becomes c = 6.5 m