Question

a ladder is placed along a Wall of a house such that its upper end is touching the top wall the foot of the ladder is 2 metre away from the wall and the ladder is making an angle of 60 degree with the level of the ground then the height of the wall is ​

Answer 1

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Answer 2

Given,

Distance between the wall and the foot of the ladder = 2m = BC

Angle made by ladder with ground (θ) = 60°

Height of the wall (H) = AB

Now, the fig. of ABC forms a right angle triangle.

So,

$\bf \: tan{θ}= \frac{Opposite \: side}{Adjacent \: side}$

$\bf \: tan \: 60° = \frac{AB}{BC}$

$\bf \sqrt{3} = \frac{AB}{5}$

$\bf \: AB = 2 \sqrt{3}$

$= > \bf \color{red} Height \: of \: the \: wall =2 \sqrt{3} \: m$