Math, asked by MrBrainlyBrilliant, 8 months ago

A ladder is placed along a wall such that its upper end is resting against a vertical wall. The foot of the ladder is 2-4 m from the wall and the ladder is making an angle of 68° with the ground. Find the height, upto which the ladder reaches.

Answers

Answered by aaravshrivastwa
12

Given :-

Angle of elevation = Ø = 68°

Horizontal distance from wall = x = 2.4 m

To find :-

• Height of the ladder upto which it reaches.

Let the height of ladder = h

This condition forms a ∆ABC.

In ∆ABC,

tanØ = h/x

Putting 'Ø = 68°' and ' x = 2.4 m' in the above equation.

tan 68° = h/2.4

Now finding the value of tan 68° in radians.

For this we just have to multiply the angle Ø with π/180°.

tan 68° = tan(68° × π/180°)

tan 68° = tan(17π/45)

tan 68° = 2.47

Again,

h = 2.4 × 2.47

h = 5.92 m

Hence,

The height upto which ladder reaches = h = 5.92 m

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Answered by sneha413639
8

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