Math, asked by sneha12614, 5 months ago

A ladder is placed in a hall resting against a wall reaching 7.5ft

above the ground. Keeping its foot at the same point, the ladder is

turned to the opposite wall to reach 12 ft above the ground. Find the

width of the hall, if the ladder is 12 feet long.

Answers

Answered by amitnrw
11

Given : A ladder is placed in a hall resting against a wall reaching 7.5f

above the ground. Keeping its foot at the same point, the ladder i

turned to the opposite wall to reach 12 ft above the ground.

ladder is 12 feet long.

or

 ladder is 12.5 feet long.

To Find : the  width of the hall

Solution:

Ladder length = Hypotenuse = 12 ft

A ladder is placed in a hall resting against a wall reaching 7.5ft

=> Perpendicular = 7.5 ft

Distance of foot of ladder from one side wall = x = Base

Base² =  Hypotenuse² - Perpendicular²

=> x² =  12² - 7.5²

=> x² =  (19.5)(4.5)

=> x² =   87.75

=> x = 9.367

other sides height = 12

=> Distance of foot of ladder from other side wall  = √12² - 12² = 0

Hence width of Hall =  9.367  + 0 = 9.367  feet  

Ladder  12.5 feet long

width of Hall =√ (12.5² - 7.5² ) + √ (12.5² - 12² )

= √ (20* 5 ) + √ (24.5*0.5 )

= √ 100 + √12.25

= 10 + 3.5

= 13.5

width of Hall  = 13.5 feet

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Answered by poorvisunil04
0

Answer:

Step-by-step explanation:

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