Question

A ladder is placed in such a way that it reaches a window 12m high from the ground on placing it against a wall at a distance xm. If the length of the ladder is 15m. Find the distance of the foot of the ladder from the wall.

Answer 1

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Answer 2

Correct question:-

A 15m long ladder reached a window 12m high from the ground on placing it against a wall at a distance a. Find the distance of the foot of the ladder from the wall

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In given figure :-

• A 15m long ladder reached a window 12m high from the ground on placing it against a wall at a distance a.

To find:-

• The distance of the foot of the ladder from the wall.

$\huge\sf{Solution:}$

AC = 15 metres long ladder

AB = 12 metres high

CB = 'a' metre.

Now,

∆ ABC is a right angled triangle.

Angle ABC = 90°.

By pythagoras Theorem :-

(AC)^2 = (BC)^2 + (AB)^2

(15)^2 = (a)^2 + (12)^2

225 = (a)^2 + 144

225 - 144 = (a)^2

81 = (a)^2

9 = a

Therefore  , 

The distance of the foot of the lader from the wall is 9 m.