Question

A ladder is placed in such a way that its foot is at a distance of 5 metre from the wall and it's tip reaches a window 12 metre about the ground. Determine the length of the ladder​

Answer 1

Answer:

first draw a triangle A, B, C.

Then take CA as 12m

AB as 5m

BC as x

as BC is the length of the ladder.

Step-by-step explanation:

then by Pythogoras Theoram

BC^2= root of 12^2 + 5^2

BC^2= root of 144 + 25

BC^2= root of 169

BC^2= 13

ANS-13

Answer 2

Step-by-step explanation:

1. Let wall height 12 m and name HP
2. Let ground is 5m and name PB
3. Ladder be HB
4. Let HB be x
5. by Pythagoras theorem
6. H^2 = P^2 + B^2
7. x^2 = 12^2 + 5^2
8. x^2 = 144 + 25
9. x^2 = 169
10. x =
11. $\sqrt{169}$
12. x = 13