a ladder leaning a vertical wall makes an angle of 45° with the ground the foot of the ladder is 3m from the wall. find the length of the ladder
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Answer:
LET AB be the wall
CB be the ladder
AC= 3cm ( given )
<ACB=45
NOW,CB/AC=sec45=root2
=CB/3
length=CB=3root 2
then,3×1.41 = 4.23 is the answer
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⚛ θ = 60° ⚛
Let the angle we need to find be θ
By the given information ,
- ♦ Adjacent side of θ = 1.5 m
- ♦ Hypotenuse of triangle = 3m
So , using cos trigonometric ratio ,
- => cosθ = 1.5/3
- => cosθ = (3/2)/3
- => cosθ = 3/2 × 1/3
- => cosθ = 1/2
Substituting , 1/2 = cos60°
- => cosθ = cos60°
By comparing ,
=> θ = 60°
Note:-
- Required Diagram is in attachment !
Attachments:
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