Question

A ladder leans against a wall makes 60ºangle with the ground. If the foot of the ladder is 4metres away from the foot of the wall, how high is the top of the ladder from the ground?

Answer 1

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${\large{\blue{\bold{\underline{Given:-}}}}}$

• Angle made by lander = 60°

• Distance b/w foot and wall = 4 meters.

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• Distance b/w the top and bottom of the ladder.

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• From given we get.

$\sf\implies \tan(60) = \frac{bc}{ab} \\ \\ \sf\implies \sqrt{3} = \frac{x}{4 \: cm} \\ \\ \sf\implies \: x = 4 \sqrt{3} \: cm$

☆ Therefore required distance is $\sf 4\sqrt{3}$

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