Question

a ladder of 10m long is leaning against a wall.the foot of the ladder is 8m away from the wall find the height upto which the ladder reaches the wall​

Answer 1

Answer:

6m

Step-by-step explanation:

It makes an right angle triangle

So, By Pythagoras theorem

ladder's height^2 = distance between ladder and

wall^2 + wall's height

10^2 = 8^2 + wall's height^2

100 = 64 + wall's height^2

wall's height^2 = 100 - 64

wall's height^2 = 34

wall's height = √34

= 6

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Answer 2

Given:

✰ Length of the ladder lying against the wall = 10 m

✰ Distance of the foot of the ladder from the wall = 8 m

To find:

✠ The height upto which the ladder reaches the wall.

Solution:

Let AC be the length of the ladder lying against the wall,

BC be the distance of the foot of the ladder from the wall, and

AB be the height upto which the ladder reaches the wall.

• Here, in this question, we need to find the height, AB. We will find AB by using Pythagoras theorem. Putting the values of hypotenuse and base, we will find height/perpendicular i.e, AB.

By using Pythagoras theorem,

➛ H² = P² + B²

Where,

• H is the hypotenuse of traingle
• P is the perpendicular
• B is the base.

➛ AC² = AB² + BC²

➛ 10² = AB² + 8²

➛ AB² = 10² - 8²

➛ AB² = (10 × 10) - (8 × 8)

➛ AB² = 100 - 64

➛ AB² = 36

➛ AB = √36

➛ AB = 6

∴ The height upto which the ladder reaches the wall = 6 m

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