Question

A ladder of 17 m length is held against a building at a distance of 8 m from the foot of the building .if the top of the pouches top the building, find the height of the building .

Answer 1

17 square = x square + 8 square
=289 - 64
=225
25 m

Answer 2

We will solve this by Pythagoras Theorem

Here the ladder is the hypotenuse the distance between ladder and building is base, Here we have to find the length of the building .

Let's start with the solution ⇒

$PR^{2} = PQ^{2} + QR^{2} \\ 17^{2} = PQ^{2} + 8^{2}\\ 289 = PQ^{2}+ 64\\ PQ^{2} = 289 - 64\\ PQ^{2} =225 \\ PQ = \sqrt{225}\\ PQ = 15$

So the height  of the building is 15 m