A ladder of 18 m reaches a point of18 m below the top of vertical flagstaff. from the foot of the ladder the angle elevation of the flagstaff is60 degree. find the height of the flagstaff.
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Answer:
Step-by-step explanation:
CD=AD=9m
∵△ACD is isosceles.
∠CAB=60°
∴∠ACB=∠CAD=30°
∴∠BAD=30°
In △ABD,
sin30°=
AD
BD
⇒BD=ADsin30°=4.5
Therefore,
BC=BC+DC=4.5+9=13.5m
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