Question

a ladder of 25 m long reaches a window of building 27000 find the distance between the foot of the ladder to the buildings

Answer 1

Let AB be ladder =25
AC be the distance from ground to window of the building =27000
And BC be the distance between foot of ladder to the building
$(ac)^{2} = (ab)^{2} + (bc)^{2}$

$(25)^2=(27000)^2+(bc)^2$
(BC)^2 =(27000)^2-(25)^2
(BC)^2=729000000 - 625
$(BC)= \sqrt{728999375}$
BC=26999.989