Question

A ladder of 25m long reaches a window 7m above the ground. The the distance of the feet of the ladder from the base of the wall is?

Answer 1

Answer: 24

Step - by - step :-

a square + b square = c square

Answer is :-

7 square + b square = 25 square

49 + b square = 625

b square = 625 - 49

b square = 576

b = √576

b = 24

Answer 2

$\huge\mathfrak\blue{Answer:}$

Given:

• We have been given that a ladder 25 m long reaches a window 7 m above the ground

To Find:

• We have to find the distance of feet of ladder from the base of wall

Solution:

Let In ∆ ABC

AB = Height of window from ground

AC = Length of ladder

BC = Distance between feet of ladder and wall

__________________

Using Pythagoras Theorm

$= > {AB}^{2} + {BC}^{2} = {AC}^{2}$

$= > {(7)}^{2} + {BC}^{2} = {(25)}^{2}$

$= > {BC}^{2} = {(25)}^{2} - {(7)}^{2}$

$= > {BC}^{2} = 625 - 49$

$= > {BC}^{2} = 576$

$= > BC = \sqrt{576}$

$= > BC = 24 \: m$

Hence the distance between feet of ladder and base of wall is 24 m