Question

A ladder of 50m height is inclined to a window of building 40m height from the ground. Then find the length between the the foot of the ladder and the building on the ground

please solve this​

Answer 1

Answer:

Let, ABC is a right angled triangle whose AB=40m and AC=50m

Therefore, (AB)^2 + (BC)^2 = (AC)^2

or, (40)^2 +(BC)^2 = (50)^2

or, 1600 + (BC)^2 = 2500

or, (BC)^2 = 2500 - 1600

or, (BC)^2 = 900

or, BC =

$\sqrt{900}$

or, BC = 30 m (ans)