A ladder of height 10 metre rests on a wall and the foot of the ladder is 6 metre away from the wall and the top of ladder reaches the top of the wall. What is the height of the wall?
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Let WA=10m be the length of the ladder and WL=xcm be the height of the wall . As wall WL=xm is vertically up so by Pythagoras theorem.
In angle angled triangle WLA
WL^2 + AL^2=WA^2
x^2 +6^2=10^2
x^2 = 10^2-6^2 = 100-36 =64 x^2 = 8
Hence , the height of the point on the wall where the top of the ladder reaches is 8m
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