Question

A ladder of lenght 10 m is leaning against a walll an angle of 60° with the horizontal plane. it touches the wall apoint A.if the ladder is rearranged in a way that it leans against the wall making angle 30° with the horizontal plane it touches the wall at point b.find the length of A B.

Answer 1

Answer:

3.66 m

Step-by-step explanation:

If we draw a right angled ∆AOD:

angle DAO = 60°.

Using value of cos 60° = 1/2.

Cos 60° = AO/AD.

Putting all the values we get

1/2 = AO / 10 .

AO = 5m.

Similarly in ∆BOD

Cos 30° = OB/BD

Cos 30° = √3/2.

Putting all the values in the above equation:

√3/2 = OB/10.

OB = 5√3.

Distance between A and B = OB - OA = 5√3 - 5 = 5(√3 - 1) = 3.66 m.

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