A ladder of length 10m is leaning against a wall making an angle of 600 with the horizontal plane. It touches the wall at point A. If the ladder is rearranged in a way that it leans against the wall making an angle 300 with the horizontal plane, it touches the wall at pointB. Find the length of AB.
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Sin60°=AC\10
√3\2=AC/10
AC=5√3m
Cos60°=DC/10
1/2=DC/10
DC=5m
tan30°=BC/5
1/√3=BC/5
BC=5√3/3
AB=AC-BC
=5√3-5√3/3
=10√3/3m
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