A ladder of length 10m is leaning against a wall making an angle of 60 degree with the horizontal plane.it touches the wall at point A.if the ladder is rearranged in a way that it leans against the wall making an angle of 30 degree with the horizontal plane.it touches the wall at point B.find the length of AB
Answers
Answer:
Let length of
A from ground be x
Let length of B from ground be y
Given:
Length of ladder =10m
The Angle of Elevation when ladder is leans against the wall at point 'A'=60degree
Also ,The Angle of Elevation when ladder is leans against the wall at point 'B'=30degree
Now
In First formed right angled triangle with Angle of Elevation we have 60degree
Sin 60= perpendicular/hypotenuse
=Lenthof A from ground/Length of the ladder
0.8660 = x/10
therefore, x=8.660m
Similarly,
In second formed right angled triangle with Angle of Elevation we have
30degree
Sin 30=perpendicular/hypotenuse
=Lenth of B from ground/Length of the ladder
0.5000=y/10
Therefore, y=5.000m
Now Length of AB= x-y
=8.660-5.000=3.66m