Question

A ladder of length 10m put on a wall of length 36 m find the distance between ladder and base of the wall

Answer 1

THE DISTANCE B/W LADDER AND BASE OF WALL IS 34.58m .

HOPE YOU UNDERSTAND....../!!!!

Answer 2

CORRECT QUESTION :

A ladder of length 36 m put on a wall of length 10 m find the distance between ladder and base of the wall.

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Distance\:between\:wall\:and\:foot\:of\:ladder=34.58\:m}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

• In the given question information given about a ladder of length 36 m put on a wall of length 10 m.

• Wh have to find the distance between ladder and base of the wall.

$\green{\underline \bold{Given :}} \\ : \implies \text{Length\:of\: ladder= 36\: m} \\ \\ : \implies \text{Heigh\:of\:wall= 100\:m} \\ \\ \red{\underline \bold{To \: Find:}} \\ : \implies \text{Distance\:between\:wall\:and\:foot\:of\: ladder = ?}$

• Accroding to given question :

$\bold{In \: \triangle \: ABC} \\ : \implies {h}^{2} = {p}^{2} + {b}^{2} \: \: \: \: \: \: \: \: \text{(by \: phythagoras \: theoram}) \\ \\ : \implies {36}^{2} = {10}^{2} + {(BC)}^{2} \\ \\ : \implies 1296= 100+(BC)^{2} \\ \\ : \implies {(BC)}^{2} =1296-100 \\ \\ : \implies BC = \sqrt{1196} \\ \\ \green{: \implies \text{BC=34.58\:m}}$